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Find a quadratic polynomial with zeroes -2 and 1/3. |
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Answer» Let the quadratic polynomial be ax2 + bx + c, a ≠ 0 and its zeroes be α and β. Here α = – 2 and β = 1/3 Sum of the zeroes = α + β = -2 + 1/3 = -5/3 Product of the zeroes = αβ = 1/3 × (-2) = -2/3 ∴ ax2 + bx + c is [x2 – (α + β)x + αβ] = [ x2 - (-5/3) x + (-2/3)] the quadratic polynomial will be 3x2 + 5x – 2. |
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