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| 1. |
Find a pythagorean triplet whose the smallest member is 10 |
| Answer» LET PYTHAGORAS TRIPLETS be 2M,m^2+1,m^2-1.now 2m=10,m=5,THEREFORE m^2+1=5^2+1=26,and m^2-1=5^2-1=24.hence triplets will be 10,24,26 | |