1.

Find a Pythagoras triplet whose one member (i) 15 (ii) 25 (iii) 10 (iv) 5.

Answer»

(2m, m2 - 1 , m2 + 1) is a pythagorean triplet

(i) Let m2 - 1 = 15

⇒ m2 = 16 = 42

⇒ m = 4

∴ 2m = 2 x 4 = 8

m2 + 1 = 16 + 1 = 17

∴ (8, 15, 17) is a pythagorean triplet.

(ii) Let m2 + 1 = 25

⇒ m2 = 24 =  4 x 6

∴ m = 2√6

∴ 2m = 4√6

& m2 - 1 = 24 - 1

∴ (4√6, 23, 25) is a pythgorean triplet.

(iii) Let 2m = 10

⇒ m2 - 1 = 25 - 1 = 24

m2 + 1 = 25 + 1 = 26

∴ (10, 24, 26) is a pythagorean triplet.

(iv) Let m2 + 1 = 5

⇒ m2 = 5 - 1 = 4 = 22

∴ m = 2

∴ 2m = 4

m2 - 1 = 4 - 1 = 3

Hence, (4, 3, 5) is a pythagorean triplet.



Discussion

No Comment Found

Related InterviewSolutions