Saved Bookmarks
| 1. |
Find a Pythagoras triplet whose one member (i) 15 (ii) 25 (iii) 10 (iv) 5. |
|
Answer» (2m, m2 - 1 , m2 + 1) is a pythagorean triplet (i) Let m2 - 1 = 15 ⇒ m2 = 16 = 42 ⇒ m = 4 ∴ 2m = 2 x 4 = 8 m2 + 1 = 16 + 1 = 17 ∴ (8, 15, 17) is a pythagorean triplet. (ii) Let m2 + 1 = 25 ⇒ m2 = 24 = 4 x 6 ∴ m = 2√6 ∴ 2m = 4√6 & m2 - 1 = 24 - 1 ∴ (4√6, 23, 25) is a pythgorean triplet. (iii) Let 2m = 10 ⇒ m2 - 1 = 25 - 1 = 24 m2 + 1 = 25 + 1 = 26 ∴ (10, 24, 26) is a pythagorean triplet. (iv) Let m2 + 1 = 5 ⇒ m2 = 5 - 1 = 4 = 22 ∴ m = 2 ∴ 2m = 4 m2 - 1 = 4 - 1 = 3 Hence, (4, 3, 5) is a pythagorean triplet. |
|