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Find a point on x-axis equidistant from A and B. |
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Answer» Let (x, 0) be a point on the x axis which is at equal distance from A and B. (2 – x)2 + (3 – 0)2 = (5 – x)2 + (4 – 0)2 (2 – x)2 + 9 = (5 – x)2 + 16 (2 – x)2 + (5 – x)2 = 16 – 9 4 – 4x + x2 – 25 + 10x – x2 = 7 6x = 28 x = \(\frac{28}{6}=\frac{14}{3}\) ∴ Point on x axis is \((\frac{14}{3},0)\) |
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