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Find a point on the x axis which is equidistant from the point (7,6) and (3,4) |
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Answer» Point on x - axis is ( x,0) not (0,y) it is point on y- axis the point on x-axis be (0,y )√(7-0)^2+(6-y)^2 =√(3-0)^2 +(4-y )^249+36+y^2-12y=9+16+y^2-8y85-12y=25-8y-12y+8y=25-85-3y=-60y=20 =Point on x-axis is (0,20).?? |
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