1.

Find a point on the x axis which is equidistant from the points A(7,6) and B(-3,4)​

Answer»

<P>Answer:

LET the POINT be p(X,y)

given that equidistance

so,

pA=pB

√(x-7)²+(y-6)²=√(x-(-3))²+(y-4)²

15=5x-y



Discussion

No Comment Found

Related InterviewSolutions