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- Find a number whose fifth part increased by30 is equal to its fourth part decreased by 30. |
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Answer» Let the number be x Its fifth part is = x/5 Its fourth part is= x/4 A.T.Q (X/5) +30 = (X/4) - 30 (X/5) -(X/4) = -30-30 (4X-5X)/20 = -60 -X = -60 *20 -X= - 1200 X= 1200------------------------------------------------------------------------------------------------------The number is 1200 ---------------------------------------------------------------------------------------------------- 1200 is correct answer. number = a; fourth part = a/4, fifth part = a/5, (a/5) + 30 = ( a/4) - 30; ( a/5)( a/4)=-30-30; (4a - 5a/20)=-60; (4a - 5a) = -60 × 20; -a = -1200,; a = 1200 1200 is the right answer plz like my answer the number is 1200 according to the above conditions. 1200 is the correct answer of the following question best answer is the 1200 x = 1200 is the right answer Let the required number be X this number fifth part increased by 30= X/5 +30and this number fourth part decreased by 30= X/4 -30=X/5 +30 = X/4 - 30=X/5 - X/4 = -30-30LCM of 5& 4 is 20=4X-5X/20 = -60=4X-5X = -60×20= -X = -1200= X = 1200So the required number is 1,200. 1200 is the answer of the following 1200 is the correct answer. please like as best |
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