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, Find α for which point (α-2-u) lies insidey^2 + 4x = 0 |
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Answer» let alpha = aput x = aand y = -2-asoy² + 4x = 0(2+a)² + 4a = 0a² + 8a + 4 = 0a = [-8 + or - √(64 -16)]/2a = [ -8 + or - √ 48 ] /2a = [-8 + or - 4√3 ] /2a = [-4 + or - 2√3] |
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