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Find a:b:c when (1) a:b=4:7 and b:c=5:3, and (2) a:b=7 1/2:3 and 1 1/4:3 |
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Answer» ong>Answer: How to do it ? —— (1) : (2) A:B = 2 : 3 B:C = 4 : 5 C:D = 6 : 7 A is the product of all TERMS APPEARING under column (1). A = 2 x 4 x 6 = 48 B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows. B = 4 x 6 x 3 = 72 C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows. C = 6 x 3 x 5 = 90 D is the product of all terms appearing under column (2). D = 3 x 5 x 7 = 105 => A:B:C:D = 48:72:90:105 hope it will be useful please follow me and MARK mi as brainleast |
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