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Find 5+10+15+...............+1000 |
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Answer» ong>Answer: The sum of 5+10+15 ….+100 is the sum of an AP WHOSE first terms is 5, the last term is 100 and the common difference is 5. Th = 100 = a +(n-1)d = 5 +(n-1)5 = 5 Sn = (n/2)[2a+(n-1)d] = (20/2)[2*5+ (20–1)*5] = 10[10+95] = 10 × 105 = 1050 Step-by-step explanation: Please mark as BRAINLIEST answer and follow me please and THANK me please Because I am a very good BOY |
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