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Find 3 consecutive even numbers such that the sum of the first and the last numbers exceed the second number by 10​

Answer»

⠀⠀⠀ ՏϴᏞႮͲᏆϴΝ

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Let the three consecutive even numbers be X, X + 2 and X + 4

As per the GIVEN statement

X + X + 4 = X + 2 + 10

➠ 2X + 4 = X + 12

➠ X = 8

Second number = X + 2 = 8 +2 = 10

Third number = X + 4= 8 + 4 = 12

The three consecutive numbers are 8,10 and 12.

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