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Find 3 A.M.'S between 3 and 19 . |
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Answer»
Here 3 is first term and 19 is SECOND term. If you insert 3 arithmatic means between them, 19 will become 5th term of Arithmatic Progression. T(n) = first term + (n-1)d. Where T(n) is n th term and d is the COMMON difference of an Arithmatic Progression. T(5) = T(1) + (5–1)d 19 = 3 + 4d This gives d = 4 There the sequence becomes 3, 3+4, 3+2*4, 3+3*4,19 3, 7, 11, 15, 19….. |
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