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Find 2nd and 3rd term of an arithmatic progression whose 1st term is 10 and common difference s 5. |
Answer» ONG>ANSWER:solutiona=10 and d=5 t1=10 t2+d=10+5=15 t3+d=15+5=20 t4+d=20+5=25 and therefore t1=10 t2=16 t3=20 t4=25 Step-by-step explanation: hope you APPRECIATE this ans |
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