1.

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Answer»

First term a= 1final term l = 118. ,and d = 3

no..of terms => 118 = 1+(n-1)3 => 3(n-1) = 118-1 = 117=> (n-1) = 117/3 = 13=> n = 13+1 = 14

so, sum = n/2*(a+l) = 14/2*(1+118) = 7*119 =833



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