Fill proper terms in the following blanks.(i) (x + 2y)² = x² + ____

1.	Fill proper terms in the following blanks.(i) (x + 2y)² = x² + ____ + 4y2(ii) (2x - 5y)² = ____ - 20xy + ____(iii) (101)² = (100 + 1)² = ____ + ____ + 1² = ____(iv) (98)² = (100 - 2)² = 10000 - ____ + ____ = ____(v) (5m + 3n)(5m - 3n) = ____ - ____ = ____ - ____
Answer» HI, Problem: Fill proper terms in the following blanks. (i) (x + 2y)² = x² + ____ + 4y2 (ii) (2X - 5y)² = ____ - 20xy + ____ (iii) (101)² = (100 + 1)² = ____ + ____ + 1² = ____ (iv) (98)² = (100 - 2)² = 10000 - ____ + ____ = ____ (v) (5m + 3N)(5m - 3n) = ____ - ____ = ____ - ____ Solution: (i) (x + 2y)² = x² + 2x(2y)+ 4y²= x² + 4xy + 4y² $(x+y)^{2} = x^{2} +2xy+y^{2}$ ∴ (ii) (2x - 5y)² = 4x² - 20xy + 25y² $(x-y)^{2} = x^{2} - 2xy+y^{2}$ ∴ (iii) (101)² = (100 + 1)² = (100)² + 2(100)(1)+ 1² =10000+200+1 = 10201 $(x+y)^{2} = x^{2} +2xy+y^{2}$ ∴ (iv) (98)² = (100 - 2)² = 10000 - 2(2)(100) +(2)² = 10000-400+4 =9604 $(x-y)^{2} = x^{2} - 2xy+y^{2}$ ∴ (v) (5m + 3n)(5m - 3n) = (5m)² - (3n)² = 25 m² - 9n² $a^{2} - b^{2}$ ∴ (a+b)(a-b) = hope it helps you.

Fill proper terms in the following blanks.(i) (x + 2y)² = x² + + 4y2(ii) (2x - 5y)² = - 20xy + (iii) (101)² = (100 + 1)² = + + 1² = (iv) (98)² = (100 - 2)² = 10000 - + = (v) (5m + 3n)(5m - 3n) = - = -

Answer»

HI,

Problem:

Fill proper terms in the following blanks.

(i) (x + 2y)² = x² + ____ + 4y2

(ii) (2X - 5y)² = ____ - 20xy + ____

(iii) (101)² = (100 + 1)² = ____ + ____ + 1² = ____

(iv) (98)² = (100 - 2)² = 10000 - ____ + ____ = ____

(v) (5m + 3N)(5m - 3n) = ____ - ____ = ____ - ____

Solution:

(i) (x + 2y)² = x² + 2x(2y)+ 4y²= x² + 4xy + 4y²

$(x+y)^{2} = x^{2} +2xy+y^{2}$ ∴

(ii) (2x - 5y)² = 4x² - 20xy + 25y²

$(x-y)^{2} = x^{2} - 2xy+y^{2}$ ∴

(iii) (101)² = (100 + 1)² = (100)² + 2(100)(1)+ 1² =10000+200+1 = 10201

$(x+y)^{2} = x^{2} +2xy+y^{2}$ ∴

(iv) (98)² = (100 - 2)² = 10000 - 2(2)(100) +(2)² = 10000-400+4 =9604

$(x-y)^{2} = x^{2} - 2xy+y^{2}$ ∴

(v) (5m + 3n)(5m - 3n) = (5m)² - (3n)² = 25 m² - 9n²

$a^{2} - b^{2}$ ∴ (a+b)(a-b) =

hope it helps you.