1.

Fill in the blanks in the following table which treats a reaction of a compound A with a compound B, that is the first order with respect to A and zero order with respect to B.

Answer»


Solution :The rate MAY be expressed as:
Rate = `k[A][B]^(@)=k[A]`
For expt. I: `(2.0 xx 10^(-2) MOL L^(-1))min^(-1) = k[A]=k(0.1 mol L^(-1))`
`k=([2.0 xx 10^(-2)mol L^(-1)]min^(-1))/(0.1 MOLL^(-1)) = 2.0 xx 10^(-1) min^(-1)`
For expt. II: Rate `=k[A]`
`therefore 4.2 xx 10^(-2) mol L^(-1) min^(-1)=2.0 xx 10^(-1) min^(-1)xx [A]`
`therefore [A] = ([4.0 xx 10^(-2) mol L^(-1)]min^(-1))/(2.0 xx 10^(-1) min^(-1))=0.2 mol L^(-1)`
For expt. III: Rate =k[A] `=(2.0 xx 10^(-1) min^(-1) xx (0.4 mol L^(-1))=8.0 xx 10^(-2) mol L^(-1) min^(-1)`
For expt. IV: Rate =k[A]
`(2.0 xx 10^(-2) mol L^(-1) min^(-1))=2.0 xx 10^(-1) min^(-1) xx [A]`
`[A]=(2.0 xx 10^(-2)molL^(-1)min^(-1))/(2.0 xx 10^(-1) min^(-1)) = 0.1 mol L^(-1)`


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