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Figure shows variation of acceleration due to gravity with distance from centre of a uniform spherical planet, Radius of planet is R. What is `r_(1) - r_(1)` A. `(R)/(4)`B. `(7R)/(4)`C. `(4R)/(3)`D. `2 R` |
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Answer» Correct Answer - B Inside planet `(9_(0))/(4)g_(0)(1-(d)/(R))rArr d=(3R)/(4)` Outside planet `g = g_(0)(R^(2))/((r+h)^(2))rArr h=R` . |
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