Figure shows two identical particles 1 and 2, each of mass m, moving in opposite directions with same speed vec V along parallel lines. At a particular instant, vec r_1 and vec r_2 are their respective position vectors drawn from point A which is in the plane of the parallel lines. Which of the following is the correct statement ? .

Figure shows two identical particles 1 and 2, each of mass m, moving i

1.	Figure shows two identical particles 1 and 2, each of mass m, moving in opposite directions with same speed vec V along parallel lines. At a particular instant, vec r_1 and vec r_2 are their respective position vectors drawn from point A which is in the plane of the parallel lines. Which of the following is the correct statement ? .
Answer» <P>Agularmomentum `I_(1)` of particlea aboutA is `I = mv (d_(1))o.` Angularmomentum`I_(2)` of particle2aboutA is ` I_(2)=mvr_(2) o.` totalangular momentumof thesystemaboutA is ` I = mv(r_(1)+r_(2))o.` totalangularmomentumof thesystemaboutA is`I=mv(d_(2)-d_(1))OX` Solution :theangularmomentum L of aparticlewithrespect tooriginis deined to be`L=rxxp` where, r is thepodsitionvectorof theparticleandp isthelinearmomentum , ThedirectionofL isis perpendicularto BOTHD rand pbyrighthand rule. Forparticle1. `I_(1) =r_(1)xxmv`is notof plane of thepaperandperpendicularto `r_(1)` andp(mv) Similarly`I_(2)=r_(2)xxm(-v)` is intotheplaneof thepaper andperpendicular to `r_(2) and -p` Hence, totalangular momentum `l=l_(1)+l_(2)=r_(1)xxmv+(-r_(2)xxmv)` `\|l\|=mvd_(1)- mvd_(2)as d_(2)gt d_(1)` totalangular momentumwillbeinward Hence `I=mv(d_(2)-d_(1))ox` note: in theexpressionof angularmomentum `I=rxxp`thedirection ofl is takenby righthand rule .