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Figure shows the variation of frequency of a characterstic x-ray and atomic number. (i) Name the characterstics x-ray (ii) Find the energy of photon emitted when this x-ray is emitted by a metal having `z=101` |
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Answer» Correct Answer - (i) `K_(alpha)` (ii) `102 KeV` From graph `gammaK(Z-1)^(2)` where `K` is constant `sqrt(v)=a(z-1) a=sqrt(K)` So its `K_(alpha)-x-ray` Energy of photon `=13.6xx(z-b)^(2)((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))` For `K_(alpha)n_(1)=1` `n=2` `E=13.6xx(100^(2))((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))` `=102 KeV` |
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