Figure shows the graph of pressure versus volume of an ideal gas, taken from state A to C via three different paths, i.e., ABC, AC and ADC. The internal energies of the gas corresponding to the states A and C are (P_0V_0) and (5P_0V_0) respectively. DetermineEquation of the straight line AC.

Figure shows the graph of pressure versus volume of an ideal gas, take

1.	Figure shows the graph of pressure versus volume of an ideal gas, taken from state A to C via three different paths, i.e., ABC, AC and ADC. The internal energies of the gas corresponding to the states A and C are (P_0V_0) and (5P_0V_0) respectively. DetermineEquation of the straight line AC.
Answer» SOLUTION :USING` (y-y_2 )/( X-x_2 ) = (y_1 -Y_2)/(x_1 -x_2 ) ` we have ` (y-P_0)/( x-2 V_0 ) = (2P_0 - P_0 )/( V_0-2 V_0) =- (P_0)/( V_0) ` `impliesY= P_0 {-(P_0)/(V_0) (x-2V_0)}=(P_0)/(V_0) ( 3 V_0 +x)`