Saved Bookmarks
| 1. |
Figure shows four plates each of plate area A and separated between plates is d. Two switches S_(w1) and S_(w_2) can activate two batteries in the circuit. Now switch S_(w_2) is opened, what is the charge on plate 4? |
|
Answer» `-5/3 (epsilon_0AV)/(d)`  When both the switches are closed, CIRCUIT is Charge on plate 2 `C_(EQ)=(2C)/(3)=(2epsilon_(0)A)/(3d)` `q_(0)=((2C)/(3))(2V)=(4CV)/(3)` Charge on plate 1 Where switch `Sw_(2)` is opened, circuit is  `[((x-V))/(-2V)]C+(x-2V)C+xC=0` or `x=(5)/(3)V` Charge on plate 4 is `-(5)/(3)CV=(-5epsilon_(0)AV)/(2d)` Alternative method `(-q_(1))/(C)+V+(q_(2))/(C)=0` or `-q_(1)+q_(2)=-CV` `(-q_(1))/(C)-((q_(1)+q_(2)))/(C)+2V=0` or `q_(1)+2q_(2)=2CV` `q_(1)=(4CV)/(3),q_(2)=(CV)/(3)` |
|