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Figure shows an irregular wedge of mass `m` placed on a smooth horizontal surface. Part `BC` is rough. If the coefficient of friction between the block and wedge is `mu`, and the block comes to rest with respect to wedge at a point `E` on the rough surface then `BE` will beA. `(H)/(mu)`B. `(H-h)/(mu)`C. `(h)/(mu)`D. none of these |
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Answer» Correct Answer - B By work `-` energy theorem on the system `:` `-(mu mg )(BE)-mgh=-(1)/(4) m u^(2)` `=-(1)/(4)m(4gH)rArr BE=(H-h)/(mu)` |
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