1.

Figure shows a soap film formed between two square figures made of a uniform wire. The bigger square is held while keeping it in a horizontal plane and the smaller square is slowly allowed to droip vertically. It reaches an equilibrium state after dropping a height h. Let surface tension of soap =T. Mass per unit length of wire =lamda. Acceleration due to gravity =g Given that h=(nlamdaga)/(2sqrt(4T^(2)-lamda^(2)g^(2))), find the integer value n.

Answer»


Solution :`TANTHETA=(3A)/(2h)`
`2xx4aTxxcostheta=4alamdag`
`costheta=(lamdag)/(2T)`
`impliesh=(3lamda GA)/(2sqrt(4T^(2)-LAMDA^(2)g^(2)))`


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