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Figure shows a semi-cylindrical massless gate pivoted at the point `O` holding a stationary liquid of density `rho`. The length of the cylinder is `l`. Calculate, the horizontal force exerted by the liquid on the gate. |
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Answer» The force exerted by liquid on the gate is `f_(H)=P_(av)xx`vertical projection area of the gate `=((P_(A)-P_(B))/2)xx(2Rl)` `=((Rrhog+3Rrhog)/2)xx2Rl=4rhogR^(2)l` |
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