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Figure shows a large tank of water at a constant temperature `theta_(0)` . and a small vessel containinng a mass m of water at an initial temperature `theta(lttheta_(0). A metal rod of length L, area of cross section A and thermal conductivity K connect the two vessels. Find the time taken for the temperature of the water in the smaller vessel to become `theta_(2)(theta_(1)lttheta_(2)lttheta_(0))` . Specific heat capacity of water is s and all other heat capacities are negligible. |
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Answer» Suppose, the temperature of the water in the smaller vessel is theta at time t. In the next time interval dt, a heat (DeltaQ) is transferred to it where `DeltaQ=(KA)/(L)(theta_(0)-theta)dt` . This heat increases the temperature of the water of mass m to `theta+d theta where `DeltaQ=msd theta` . From (i) and (ii), (KA)/L(theta_(0)-theta)dt=msd theta` . or, `dt=(Lms)/(KA)(d theta)/(theta_(0)-theta` . or, `int_(0)^(T)dt=(Lms)/(KA)int_(theta_(1))^(theta^(2))(d theta)/(theta_(0)-theta)` . where T is the time requierd for the temperature of the water to become `theta_(2)` . Thus, `T=(Lms)/(KA) ln `(theta_(0)-theta_(1))/(theta_(0)-theta_(2))` . |
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