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Figure shows `4` identical masses of mass `m`, arranged on a cube as shown. The potential energy of the system is A. `2sqrt(2)(Gm^(2))/(a)`B. `3sqrt(2)(Gm^(2))/(a)`C. `-2sqrt(2)(Gm^(2))/(a)`D. `-3sqrt(2)(Gm^(2))/(a)` |
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Answer» `PE=6xx(GM^(2))/(sqrt(2)a)` `=-3sqrt(2)(GM^(2))/(a)` `F=3xx(GM^(2))/(2a^(2))xx(sqrt(2))/(sqrt(3))=sqrt((3)/(2))(GM^(2))/(a^(2))` |
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