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Figure shows `4` identical masses of mass `m`, arranged on a cube as shown. The force on any particle isA. `(3)/(2)(GM^(2))/(a^(2))`B. `sqrt((3)/(2))(GM^(2))/(a^(2))`C. `sqrt(6)(GM^(2))/(a^(2))`D. none of these |
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Answer» `PE=6xx(GM^(2))/(sqrt(2)a)` `=-3sqrt(2)(GM^(2))/(a)` `F=3xx(GM^(2))/(2a^(2))xx(sqrt(2))/(sqrt(3))=sqrt((3)/(2))(GM^(2))/(a^(2))` |
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