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Figure shown a hydraulic press with the larger piston if diameter 35 cm at a height of 1.5 cm at a height of 1.5 m relative to the smaller piston of diameter 10cm. The mass on the smaller piston is 20 kg. What is the force exerted on the load by the larger piston? The density of oil in the press is `750 kh//m^(3)` . (Take `g=9.8 m//s^(2))` . |
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Answer» Correct Answer - A::C Pressure on the smaller piston `= (20xx9.8)/(pi xx(5xx10^(-2))^(2))N//m^(2)` Pressure on the larger piston`=(F)/(pixx(17.5xx10^(-2))^(2)) N/m^(2)` The difference between the two pressure `=h rho g` where, `h=1.5 m` and ` rho=750 kg//m^(3)` Thus, `(20xx9.8)/(pi xx(5xx10^(-2))^(2))-(F)/(pixx(17.5xx10^(-2))^(2))=1.5xx750xx9.8` which gives, `F=1.3xx10^(3)N`. |
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