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Figure here gives the speed-time graph for a body. The distance travelled between I = 1.0 second and t = 7.0 second is nearest to: |
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Answer» Solution :Here the AREAS from t=1 sec. to t =7 sec are From t=1 to t=2 `x_1=1xx2+(1)/(2)xx1xx2=3 m` From t=2 to t=3 `x_21xx4=4m` From t=3 to t=4 `x_3=(1)/(2)xx1xx4=2 m` From t4 to t=5 `x_4=(1)/(2)xx1xx-4= -2m` Net distance =3+4+2-2-4=3m. |
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