1.

Figure depicts the working diagram (P-V graph) of a process corresponding to an ideal gas. Suppose U_A=10J, U_B = 50 J and heat given to the gas during the process BC is 40 J. Determine Internal energy of the gas in the state C.

Answer»

Solution :WORK done by the gas during the process
BC = AREA below the graph `= -1/2 (20+50) (N )/(m^2) xx(6-2)m^3=-140 J`
Now, APPLYING first law of thermodynamics to the process BC,
`Delta Q =Delta U+ Delta W`
`40J = Delta U+(-140J)`
` thereforeDelta U = 180J`
i.e., `(U_c-50 J) = 180 J, or U_c = 230J`


Discussion

No Comment Found