1.

Fig.8.8/12. In Fig. 8.88, PQ is a chord of a circle and PT is the tangent at Psuch that zQPT6INCERT EXEMPLAR)Then, find ZPRQ女"

Answer»

Given,PQ is a chord of a circle with center O. Also, ∠QPT = 60°.let x be the point on the tangent PT.

Now, ∠QPT + ∠QPX = 180° [Linear pair]

⇒ ∠QPX = 180° - ∠QPT = 180° - 60° = 120°

Again, ∠QPX = ∠PRQ [Alternate segment theorem]

⇒ ∠PRQ = 120°



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