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Fig.8.8/12. In Fig. 8.88, PQ is a chord of a circle and PT is the tangent at Psuch that zQPT6INCERT EXEMPLAR)Then, find ZPRQ女" |
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Answer» Given,PQ is a chord of a circle with center O. Also, ∠QPT = 60°.let x be the point on the tangent PT. Now, ∠QPT + ∠QPX = 180° [Linear pair] ⇒ ∠QPX = 180° - ∠QPT = 180° - 60° = 120° Again, ∠QPX = ∠PRQ [Alternate segment theorem] ⇒ ∠PRQ = 120° |
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