1.

Fid the sum all natural no less then 200 which are divisble 5

Answer»

A = 5

d = 5

L = 195

=> a + (n-1)d = 195

=> 5 + (n-1)(5) = 195

=> (n-1)(5) = 190

=> n - 1 = 38

=> n = 39

SN = 39/2 [ 5 + 195]

= (39)(200) /2

= 39 × 100

= 3900

Required sum = 3900



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