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Fiad the melanty andmotdl:ttity or a 15% solutionCat masses e t,Dole, s-32) |
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Answer» 15% H₂SO₄ solution means 15 g of H₂SO₄ is present in 100 g of Water.No. of moles of H₂SO₄ = 15 g / 98 g/mol = 0.153 molWeight of solvent = 100g - 15g = 85g = 85 × 10^-3 kg Molality = Moles of solute / Weight of Solvent in kg= 0.153 / (85 × 10^-3)= 1.8 mMolality of given solution is 1.8 m ……[1] Volume of solution = Mass of solution / Density= 100 g / 1.02 g/cm^3= 98.04 cm^3= 0.098 Litres Molarity = Moles of solute / Volume of solution in litres= 0.153 / 0.098≈ 1.56 MMolarity of given solution is 1.56 M ……[2] |
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