Yeah sure for your help

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AS in this series of alphabet We have to find the ANALOGICAL series as the better way to solve this question is we have to taken this alphabets in number series as it is a easy way to solve that type of questions

FHJL :- In the following alphabets

F =6

H=8

j= 10

L=12

Clearly , in this you are ABLE to see that there is a difference of two between each of the numbers

GIFH :- LET us convert it as number form

G = 7

I = 9

F=6

H=8

What we have see in this numbers ??

Let us solve it in this way

FHJL :- 6 , 8, 10, 12

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GIFH :- 7,9,6,8

Compare each of the number with the down no. or the denominator of the number

For instance compare F with G there is a addition of 1 we have seen similarly in H and I there is also addition of number. Between J or F and L or H there is a difference of -4

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Well , now it is a final solution of this question

NPMO :-

N=14

P=16

M=13

O=15

Clearly , you see that it is similar to GIFH

So, for final or correct answer we solve it as

N = 14 -1

=> 13

P = 16- 1

=>15

M =13 -4

=> 9

O = 15 - 4

=> 11

13 , 15 , 9 , 11 in alphabet form it is MOIK

So , the solution of this question is NPMO : MOIK

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@Brainlestuser