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Feed of a reactor has 0.75 mass fraction of O2 and some SO2, if the product rate is 1000 Kg/hr then what is the rate of SO2 in the feed?(a) 100 Kg/hr(b) 250 Kg/hr(c) 750 Kg/hr(d) 1000 Kg/hr |
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Answer» Correct option is (b) 250 Kg/hr The best explanation: Feed rate = Product rate = 1000 Kg/hr, => Rate of SO2 = (1 – 0.75)*1000 = 250 Kg/hr. |
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