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Fanula inet use. |
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Answer» (a+b)³ = (a+b)(a+b)(a+b) = [(a+b)(a+b)](a+b) = [a²+b²+2ab](a+b) = [a³+a²b+ ab²+b³+2a²b+2ab²] = [a³+b³+3a²b+3ab²] = [a³+b³+3ab(a+b)] now, (a+b)³ = a³+b³ +3ab(a+b) so, a³ +b³ = (a+b)³ - 3ab(a+b) |
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