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Faliate -22-222 |
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Answer» let x =√-2+2√-2+2√....∞here √-2+2√ is repeating so it can be substituted as x so, x = √(-2+2x) => x²= -2+2x so, x²-2x+2 = 0 => x = 2±√4-4.(2)/2 = 1±2i the value of x = 1-2i , 1+2i. |
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