1.

Factorize x^2-4x+1 and also find its zero

Answer»

Answer:-

→x²-4x+1=0

๛S=-4[Sum of EQUATION]

๛P=1[Product of Equation]

[•°• There is no COMMON factor we will use DISCRIMINANT FORMULA]

→d=b²-4ac

a=1,b=-4,c=1

→d=(-4)²-4×1×1

→d=16-4

→d=12

→√d=±√12

→√d=±2√3

[♦Refer ATTACHMENT for √12 factorization♦]

\rule{200}{1}

Taking X(+)=\frac{-b+\sqrt{d}}{2a}

๛x=\frac{-(-4)+2 \sqrt{3}}{2×1}

๛x=\frac{4+2 \sqrt{3}}{2}

๛x=\frac{\cancel{2}(2+ \sqrt{3})}{\cancel{2}}

๛x=2+√3

\rule{200}{1}

Taking x(-)=\frac{-b-\sqrt{d}}{2a}

๛x=\frac{-(-4)-2 \sqrt{3}}{2×1}

๛x=\frac{4-2 \sqrt{3}}{2}

๛x=\frac{\cancel{2}(2- \sqrt{3})}{\cancel{2}}

๛x=2-√3

\rule{200}{2}

๛x=2±√3

\rule{200}{3}



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