1.

Factorize: a2+4b2-4ab-4c2

Answer»

Given, 

a2 +4b2-4ab-4c2 = (a)2+ (2b)2 – 2×a×2b-4c2 

= (a-2b)2 – (2c)

= (a-2b-2c)(a-2b+2c)



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