1.

Factorize-(a+b)^(3)+(b+c)^(3)+(c+a)^(3)-3(a+b)(b+c)(c+a)

Answer»

ANSWER:

a3 + b3 + C3 - 3abc = (a + b + c )(a2 + b2 + C2 -ab - AC -bc) Now it is given that : a3 + b3 + c3 = 3abc. So, a3 + b3 + c3 - 3abc = 0.



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