Factorize 2x^3-x^2-15x+18 in synthetic division method

1.	Factorize 2x^3-x^2-15x+18 in synthetic division method
Answer» Answer: Here x = 2 is ZERO of POLYNOMIAL (by hit & trial) so (x - 2) is one factor. Now $2 {x}^{3} - {x}^{2} - 15x + 18 = 2 {x}^{3} - 4 {x}^{2} + 3 {x}^{2} - 6x - 9x + 18 =$ $2 {x}^{2} (x - 2) + 3x(x - 2) - 9(x - 2) = (x - 2)(2 {x}^{2} + 3x - 9)$ $(x - 2)(2 {x}^{2} + 6x - 3x - 9) =$ $(x - 2)(2x(x + 3) - 3(x + 3)) =$ $(x - 2)(x + 3)(2x - 3)$ Required factor. Hope this will HELP you. Pls mark BRAINLIEST. Thanks

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