1.

Factorize 27x^3+y^3+z^3-9xyz using identity

Answer» HEY friend...
Here is your answer


27x3 + y3 + z3 - 9xyz
              = (3X)3 + y3 + z3 - 3 × (3x) × y × z  
              = [3x + y + z ][(3x)2 + y2 + z2 - (3x) × y − y × z  − z(3x)] [SINCE  (a + b + c )(A2 + y2 + z2 - ab−bc−ca)]
              = [3x + y + z ][9x2 + y2 + z2 - 3xy − YZ  − 3zx

I hope it will help you
#yahyaahmad#


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