Factorization 2y^2-5y+2

1.	Factorization 2y^2-5y+2
Answer» ANSWER: $2 {y}^{2} - 5y + 2 = 0 \\ = 2y {}^{2} - 4y - y + 2 = 0 \\ = 2y(y - 2) - 1(y - 2) = 0 \\ = (y - 2)(2y - 1) = 0 \\ = y = 2 \: \: and \: \: \frac{1}{2}$ HEY! MATE Here is your SOLUTION. THANKS

Answer»

$2 {y}^{2} - 5y + 2 = 0 \\ = 2y {}^{2} - 4y - y + 2 = 0 \\ = 2y(y - 2) - 1(y - 2) = 0 \\ = (y - 2)(2y - 1) = 0 \\ = y = 2 \: \: and \: \: \frac{1}{2}$

HEY! MATE Here is your SOLUTION. THANKS

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Factorization 2y^2-5y+2​

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Factorization 2y^2-5y+2