1.

Factorise9(2a-b)^2-4(2a-b)-13

Answer»

Answer:

(18a – 9b – 13)(2a – B + 1)

Step-by-step explanation:

9 × (2a – b)² – 4 × (2a – b) – 13

[Let (2a – b) be a]

= 9a² – 4a – 13

= 9a² – 13a + 9A – 13   {Middle term break}

= a(9a – 13) + (9a – 13)

= (9a – 13)(a + 1)

[Putting the VALUE of a BACK]

= [9(2a – b) – 13)[ (2a – b) + 1]

= (18a – 9b – 13)(2a – b + 1).

Hope it helps...please mark as BRAINLIEST.


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