Factorise (x-2y) the whole cube + (2y-3z) the whole cube + (3z-x) the

1.	Factorise (x-2y) the whole cube + (2y-3z) the whole cube + (3z-x) the whole cubeHelp me do it with the steps.Plsss
Answer» Answer: given (x-2y)^3 + (2y-3z)^3 + (3z-x)^3 we KNOW that if a + B + C = 0 then a^3 + b^3 + c^3 = 3abc here a = (x-2y) b = (2y-3z) c = (3z-x) (x-2y)^3 + (2y-3z)^3 + (3z-x)^3 = 3(x-2y)(2y-3z)(3z-x)

Factorise (x-2y) the whole cube + (2y-3z) the whole cube + (3z-x) the whole cubeHelp me do it with the steps.Plsss

Answer»

Answer:

given (x-2y)^3 + (2y-3z)^3 + (3z-x)^3

we KNOW that if a + B + C = 0

then a^3 + b^3 + c^3 = 3abc

here a = (x-2y)

b = (2y-3z)

c = (3z-x)

(x-2y)^3 + (2y-3z)^3 + (3z-x)^3 = 3(x-2y)(2y-3z)(3z-x)

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Factorise (x-2y) the whole cube + (2y-3z) the whole cube + (3z-x) the whole cubeHelp me do it with the steps.Plsss

we KNOW that if a + B + C = 0

then a^3 + b^3 + c^3 = 3abc

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