Factorise the expressions and divide64(x4– 5x3– 24x2) ÷ (16 x2-12

1.	Factorise the expressions and divide64(x4– 5x3– 24x2) ÷ (16 x2-128x)
Answer» SIMPLIFY: Step-by-step EXPLANATION: $\ Given \ that: \\\\\ 64(x^4-5x^3-24x^2) \div (16x^2-128x)\\\\\ slove:\\\\\rightarrow \frac {64(x^4-5x^3-24x^2)} {(16x^2-128x)}\\\\\ common \ value \ from \ numerator \ and \ denominator \ part: \\\\\rightarrow \frac {64x(x^3-5x^2-24x)} {16x(x-8)}\\\\\rightarrow \frac {4(x^3-5x^2-24x)} {(x-8)}\\\\\rightarrow \frac {4x(x^2-5x-24)} {(x-8)}\\\\\rightarrow \frac {4x(x^2-(8-3)x-24)} {(x-8)}\\\\\rightarrow \frac {4x(x^2-8x+3x-24)} {(x-8)}\\\\\rightarrow \frac {4x(x(x-8)+3(x-8))} {(x-8)}\\\\$ $\rightarrow \frac {4x(x-8)(x+3)} {(x-8)}\\\\\rightarrow 4x(x+3)\\\\$ LEARN more: FACTORISE: brainly.in/question/8919211

Factorise the expressions and divide64(x4– 5x3– 24x2) ÷ (16 x2-128x)

Answer»

SIMPLIFY:

Step-by-step EXPLANATION:

$\ Given \ that: \\\\\ 64(x^4-5x^3-24x^2) \div (16x^2-128x)\\\\\ slove:\\\\\rightarrow \frac {64(x^4-5x^3-24x^2)} {(16x^2-128x)}\\\\\ common \ value \ from \ numerator \ and \ denominator \ part: \\\\\rightarrow \frac {64x(x^3-5x^2-24x)} {16x(x-8)}\\\\\rightarrow \frac {4(x^3-5x^2-24x)} {(x-8)}\\\\\rightarrow \frac {4x(x^2-5x-24)} {(x-8)}\\\\\rightarrow \frac {4x(x^2-(8-3)x-24)} {(x-8)}\\\\\rightarrow \frac {4x(x^2-8x+3x-24)} {(x-8)}\\\\\rightarrow \frac {4x(x(x-8)+3(x-8))} {(x-8)}\\\\$