Factorise it49-81x^2

1.	Factorise it49-81x^2
Answer» Answer: Rewrite 49 as 72 . Rewrite 81x2 81 x 2 as (9x)2 ( 9 x ) 2 . Since both terms are PERFECT SQUARES, factor USING the difference of squares FORMULA, a2−b2=(a+b)(a−b) a 2 - b 2 = ( a + b ) ( a - b ) where a=7 and b=9x b = 9 x

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Answer:

Rewrite 49 as 72 . Rewrite 81x2 81 x 2 as (9x)2 ( 9 x ) 2 . Since both terms are PERFECT SQUARES, factor USING the difference of squares FORMULA, a2−b2=(a+b)(a−b) a 2 - b 2 = ( a + b ) ( a - b ) where a=7 and b=9x b = 9 x

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Factorise it49-81x^2​

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Factorise it49-81x^2