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Factorise fast plz |
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Answer» Answer: \BEGIN{gathered}p {q}^{4} - p(p - q) ^{4} \\ = p( {q}^{4} - (p - q) ^{4} ) \\ = p( {q}^{2} + (p - q) ^{2} )( {q}^{2} - (p - q) ^{2} )\\ = p( {q}^{2} + {p}^{2} + {q}^{2} - 2PQ)(q + p - q)(q - p + q) \\ = p(2 {q}^{2} + {p}^{2} - 2pq)(p)(2Q - p) \\ = {p}^{2} (2 {q}^{2} + {p}^{2} - 2pq)(2q - p) \end{gathered} pq 4 −p(p−q) 4
=p(q 4 −(p−q) 4 ) =p(q 2 +(p−q) 2 )(q 2 −(p−q) 2 ) =p(q 2 +p 2 +q 2 −2pq)(q+p−q)(q−p+q) =p(2q 2 +p 2 −2pq)(p)(2q−p) =p 2 (2q 2 +p 2 −2pq)(2q−p)
This is your answer.༎ຶ‿༎ຶ |
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