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Factorise by using identity |
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Answer» HI !! ( a + B )² - 49 ( a - b )² Using identity , ( a + b)² = a² + b² + 2AB and ( a - b)² = a² + b² - 2ab. Therefore, ( a)² + ( b)² + 2ab - 49 [ ( a² + b² - 2ab ) ] a² + b² + 2ab - 49a² - 49b² + 98ab a² - 49a² + b² - 49b² + 2ab + 98ab -48a² - 48b² + 100ab -4 ( 12a² + 12b² 25ab) [ ANSWER ] |
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