1.

Factorise by using identity

Answer» HI !!

( a + B )² - 49 ( a - b )²



Using identity , ( a + b)² = a² + b² + 2AB and ( a - b)² = a² + b² - 2ab.


Therefore,

( a)² + ( b)² + 2ab - 49 [ ( a² + b² - 2ab ) ]

a² + b² + 2ab - 49a² - 49b² + 98ab

a² - 49a² + b² - 49b² + 2ab + 98ab

-48a² - 48b² + 100ab

-4 ( 12a² + 12b² 25ab) [ ANSWER ]


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