Factorise and find the zeros: x²-3√3+6

1.	Factorise and find the zeros: x²-3√3+6
Answer» Answer: Step-by-step EXPLANATION: Between x^2 and 3root3x and 6, there is plus sign. x^2 + 3root3 x + 6 = {x}^{2} + 3 \sqrt{3} x + 6 \\ \\ = {x}^{2} + 2\sqrt{3} x + \sqrt{3} x + 6 \\ \\ = x(x + 2 \sqrt{3} ) + \sqrt{3} (x + 2 \sqrt{3} ) \\ \\ = (x + 2 \sqrt{3} )(x + \sqrt{3} )

Answer»

Answer:

Between x^2 and 3root3x and 6, there is plus sign.

x^2 + 3root3 x + 6

= {x}^{2} + 3 \sqrt{3} x + 6 \\ \\ = {x}^{2} + 2\sqrt{3} x + \sqrt{3} x + 6 \\ \\ = x(x + 2 \sqrt{3} ) + \sqrt{3} (x + 2 \sqrt{3} ) \\ \\ = (x + 2 \sqrt{3} )(x + \sqrt{3} )

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Factorise and find the zeros: x²-3√3+6

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